MediumProbabilityAcceptance 69%

Poisson — No Arrivals

Two SigmaJump Trading

Calls arrive as a Poisson process at a rate of 3 per hour. What is the probability of receiving no calls in the next hour? (Round to 4 decimals.)

Approach

P(0 events) for Poisson(λ) is e−λe^{-\lambda}.

Answer

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The answer is 0.0498. Sign in free for the full worked solution and to check your own answer.

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